An open box has a square base and a volume of 32 in3. find the dimensions of the box, assuming a minimum amount of material is used in its construction.
For minimum material to be used, the box should be a cube. Hence the volume will be as follows: let the dimensions be x in by x in by x in thus V=x×x×x 32=x³ in³ hence: x=∛32 x=2∛2 inches Hence the length=width=height=2∛2
