A technician is launching fireworks near the event of a show. Of the remaining 11 fireworks, 4 are blue and 7 are red. If she launches 6 of them what’s the probability that 2 of them will be blue

Respuesta :

[tex] \displaystyle
|\Omega|=\binom{11}{6}=\dfrac{11!}{6!5!}=\dfrac{7\cdot8\cdot9\cdot10\cdot11}{2\cdot3\cdot4\cdot5}=462\\
|A|=\binom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{3\cdot4}{2}=6\\\\
P(A)=\dfrac{6}{462}=\dfrac{1}{77}\approx1\% [/tex]

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