Respuesta :

[tex]\sin(\theta) = \dfrac{\text{opp}}{\text{hyp}}[/tex]

[tex]\sin(45) = \dfrac{6 \sqrt{2} }{x} [/tex]

[tex]x= \dfrac{6 \sqrt{2} }{\sin(45)} [/tex]

[tex]x= 12[/tex]

datgamer13
I believe the answer is D) 12\/-2  (I don't know how to write it with a normal keyboard. lol) Because sides A and B are both 6\/-2.  A^2 + B^2 = C^2

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