Respuesta :
To solve this problem, first we need to figure out what fraction of the class are boys.
If we know that 4/7 of the students are girls, there are only 3/7 students left in the class, therefore they must be boys.
We know that there are 9 boys in the class. (Let the variable x represent how many students total there are in the class.)
3/7x=9
If we divide both sides by 3/7, we get
x=21.
Therefore, there are 21 students in the class. Your answer is C. 21.
If we know that 4/7 of the students are girls, there are only 3/7 students left in the class, therefore they must be boys.
We know that there are 9 boys in the class. (Let the variable x represent how many students total there are in the class.)
3/7x=9
If we divide both sides by 3/7, we get
x=21.
Therefore, there are 21 students in the class. Your answer is C. 21.
4/7 are girls
9 are boys
total=boys+girls=4/7+boys
boys=9
total=7/7
7/7=4/7+boys
subtract 4/7 from both sides
3/7=boys
therefor
3/7 of class=9
multily oth sides by 7/3 to clear fraction
class=63/3=21
class=21
answe ris C 21
9 are boys
total=boys+girls=4/7+boys
boys=9
total=7/7
7/7=4/7+boys
subtract 4/7 from both sides
3/7=boys
therefor
3/7 of class=9
multily oth sides by 7/3 to clear fraction
class=63/3=21
class=21
answe ris C 21