Respuesta :

To solve this problem, you need to solve the given equation.

n+(n+2)+(n+4)=42
n+n+2+n+4=42
3n + 6 = 42
3n = 36
n=12

This means that the first starting number is 12.  So the 3 consecutive even numbers would be 12, 14, and 16.

To check this, we can add these numbers together, and see if we get a sum of 42.

12+14+16=42, therefore your answer is correct.

apologiabiology
so consecutive even numbers are 2 away from each other so therefor th enumbers are
x,x+2,x+2+2
so the add upt o 42
x+x+2+x+2+2=42
add like terms
3x+6=42
subtract 6 from both sides
3x=36
divide by 3
x=12
numbers are x,x+2,x+4
12+2=14
12+4=16
numbers are 12,14,16

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