a) I know that the take off height is 25m. I also know that the horizontal distance to cover is 135m.
b) I need to solve the take off horizontal speed from the height.
c) The equation is Horizontal distance, x = Horizontal speed u * time t.
x = ut
H = (1/2)gt^2. Taking g as 10 m/s^2
Where H = Take off height from the ground.
Using second equation:
H = (1/2)gt^2
25 = (1/2)*10* t^2
25 = 5t^2
5t^2 = 25
t^2 = 5. Therefore, t = √5 seconds.
Using x = ut
125 = u * √5
u = 125/√5. Expressing as surd u = 25√5 m/s.
Using your calculator, u = 55.90 m/s.
