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The principal square root of 49 is just 7 because 7 times 7 is 49.
It can not be -7 because a principle square root cannot be negative.

[tex]\sf\ Answer: A)\ 7[/tex]

[tex]\sf\ \sqrt{49}=\\\±7\\\\-7\ and\ 7\ are\ both\ square\ roots\ of\ 49\ because\ 7\times7=49\ and\\\\-7\times-7=49.\\\\But\ as\ I\ said\ before,\ principal\ square\ roots\ can\ not\ be\ negative\\\\numbers.\\\\That\ will\ eliminate\ any\ options\ with\ -7.\\\\So\ the\ only\ principal\ square\ root\ that\ we\ have\ is\ {\boxed{7}[/tex]
The answer would be 7 
because the square root of 49 is 7
so 7 multiplied 7 is ..49

The answer wont be -7 because in Principal root, 
negative numbers are not involved, you cant do it! :)

That being said you'd also be able to know that since no negative numbers are allowed in principle root, -7 and 7 are out as choices, and D is totally wrong since we now know what the priniciple root means :)
The answer is 7
Hope this helped !

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