In the question , it is given that Jack is learning to ride a bicycle. in his first try, he rode for 4/100 mile, the second time he rode for 6/100 mile. In the next two tries, he rode successfully for 2/10 mile and 3/10 mile.
We have to find the total distance , and for that we have to add all the distances he rode, that is
[tex] \frac{4}{100} + \frac{6}{100} + \frac{2}{10}+\frac{3}{10} [/tex]
Making all the denominator equal, by multiplying the last two numerators and denominators by 10
[tex] \frac{4}{100} + \frac{6}{100} + \frac{20}{100}+\frac{30}{100} [/tex]
Now since the denominators are same, so we have to add the numerators, that is
[tex] \frac{4+6+20+30}{100} = \frac{60}{100} = \frac{3}{5} miles [/tex]
In the second part, we have to find the total distance travelled in decimal , which is 0.6 miles .
