Answer:
0.99 s
Explanation:
The period of a simple pendulum is given by:
[tex]T=2 \pi \sqrt{\frac{L}{g}}[/tex]
where
L is the length of the pendulum
g is the acceleration due to gravity
In this problem, we have
[tex]L=24.6 cm=0.246 m[/tex]
[tex]g=9.81 m/s^2[/tex]
Substituting into the equation, we find the period:
[tex]T=2 \pi \sqrt{\frac{0.246 m}{9.81 m/s^2}}=0.99 s[/tex]
