i need trigometry help

a^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.

Answer Link

keshavgandhi04 keshavgandhi04 · Answer 2 · 2022-08-13T08:20:56+02:00

The angle A, B, and C will be 19.16°, 42.228°, and 118.61° respectively.

What is a triangle?

A triangle is a 3-sided shape that is occasionally referred to as a triangle. There are three sides and three angles in every triangle, some of which may be the same.

The sum of all three angles inside a triangle will be 180° and the area of a triangle is given as (1/2) × base × height.

Given the triangle with three sides,

By cosine law,

CosC = (225² + 270² - 442.85²)/(2 × 225 × 270)

Cos C = - 0.478

C = 118.61°.

Cos A = ( 255² + 442.85² - 270²)/(2 × 255 × 442.85 )

Cos A = 0.944

A = 19.16°.

Now since in a triangle sum of all angle are 180°

So,

A + B + C = 180°

B = 180 - A - C

B = 180 - 19.16 - 118.61

B = 42.228°.

Hence angles A, B and C will be 19.16°, 42.228°, and 118.61° respectively.

For more about triangles,

https://brainly.com/question/2773823

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