Answer: Probability that [tex]x>7y[/tex] is [tex]\frac{287}{4020}[/tex]
Step-by-step explanation:
Since we have given that
[tex]x>7y[/tex]
And the coordinates are as follows:
(0,0),(2009,0),(2009,2010), and (0,2010)
We need to find the probability that [tex]x>7y[/tex]
So, Required Probability is given by
[tex]\frac{\text{Area of triangle}}{\text{ Area of rectangle}}\\\\=\frac{0.5\times 2009\times 287}{2009\times 2010}\\\\=\frac{287}{4020}[/tex]
Hence, Probability that [tex]x>7y[/tex] is [tex]\frac{287}{4020}[/tex]
Answer:
Hence, the probability is:
[tex]\dfrac{287}{4020}[/tex]
Step-by-step explanation:
We know that probability of an event is defined as:
Probability=(Number of favourable events)/(Total number of events)
The probability that x > 7y is given by:
Here the number of favourable event is equal to the area covered by the triangle ΔABE
Area of triangle ABE= (1/2)×b×h=(1/2)×2009×287=288291.5
and the total outcome is equal to the area of the rectangle (i.e. rectangle ABCD)
Area of rectangle ABCD=2009×2010=4038090
Hence, probability=
[tex]\dfrac{288291.5}{4038090}=\dfrac{287}{4020}[/tex]
