Answer:
180.5 in²
Step-by-step explanation:
In the given question diagonals of the kite have been given as
[tex]D_{1}[/tex] = 2 × 9.5 = 19 inches
[tex]D_{2}[/tex] = 7 + 12 = 19 inches
Since kite is always in the shape of a rhombus and area of a rhombus is represented by
[tex]\frac{1}{2}D_{1}[/tex] × [tex]D_{2}[/tex] Â
So area of the kite = [tex]\frac{1}{2}[/tex] × 19 × 19
                = [tex]\frac{361}{2}[/tex]
                = 180.5 in²
Therefore, material required to prepare the kite will be 180.5 in²