Respuesta :

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Y=7x^2-3
X= 7y^2 -3
X+3=7y^2
7(x+3)= y^2
7x+21= y^2
Square root of (7x+21) = y

The inverse is: y= square root of (7x+21)

The inverse of the given relation should be [tex]\sqrt{7x + 21}[/tex]

Given that,

The relation is [tex]y= 7x^2-3[/tex]

  • The calculation is as follows:

[tex]Y=7x^2-3\\\\X= 7y^2 -3\\\\X+3=7y^2\\\\7(x+3)= y^2\\\\7x+21= y^2\\\\\sqrt{ 7x+21} = y[/tex]

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