A school fair ticket costs $8 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who went to the fair was 30, and the total money collected was $100. Which of the following options represents the number of children and the number of adults who attended the fair that day, and the pair of equations that can be solved to find the numbers? 20 children and 10 adults


Equation 1: a + c = 30 Equation 2: 8a + c = 100 10 children and 20 adults

Equation 1: a + c = 30 Equation 2: 8a − c = 100 10 children and 20 adults

Equation 1: a + c = 30 Equation 2: 8a + c = 100 20 children and 10 adults

Equation 1: a + c = 30 Equation 2: 8a − c = 100

Respuesta :

The answer will be Equation 1: a + c = 30
Equation 2: 8a + c = 100, where 20 children and 10 adults.

The option that represents the number of children and the number of adults who attended and the pair of equations is; Option C

How to create equation from Algebra wor problems?

We are told that the total number of adults (a) and children (c) who went to the fair was 30. Thus;

Equation 1: a + c = 30

A school fair ticket costs $8 per adult and $1 per child. Total money collected was $100. Thus;

Equation 2: 8a + c = 100

Solving both equations simultaneously, we have 20 children and 10 adult

Read more about Algebra equations at; https://brainly.com/question/13818690

Q&A Education