Given that a city council consists of six democrats and seven republicans, the probability of selecting three democrats and two republicans if a committee of five people is to be selected is given by
[tex] \frac{ ^6C_3\times ^7C_2}{ ^{13}C_5} = \frac{20\times21}{1,287} \\ \\ = \frac{420}{1,287} =0.3263[/tex]
