Respuesta :
This is a typo and vaguely phrased. However, the closest to a direct solution is to think of it as follows: 35% of the cars are speeding. Out of these, 52% of the cars are also speeding. Hence, the result of cars that are both speeding and speed cars is 0.52*0.35=0.182
The probability that a randomly selected car along the same portion of the highway was a speeding sports car [tex]\boxed{0.182{\text{ or 18}}{\text{.2\%}}}[/tex].
Further Explanation:
The independent probabilities of two sets can be calculated as follows,
[tex]\boxed{P\left({A \cap B}\right)=P\left(A\right)\times P\left(B\right)}[/tex].
Here, A represents the first event and B represents the second event.
Given:
In traffic data there are 35 percent of automobiles.
There 52 percent of sports cars that are speeding on the highway.
Calculation:
Let A denote the event that a vehicle travelling on the highway is an automobile.
The probability of event A can be calculated as follows,
[tex]\begin{aligned}P\left(A\right)&=35\%\\&=0.35\\\end{aligned}[/tex]
Let B denote the event that an automobile is a speeding sports car.
The probability of event B can be calculated as follows,
[tex]\begin{aligned}P\left(B\right)&=52\%\\&=0.52\\\end{aligned}[/tex]
The probability that a randomly selected car along the same portion of the highway was a speeding sports car can be calculated as follows,
[tex]\begin{aligned}{\text{Probability}}&=0.52\times0.35\\&=0.182\\\end{aligned}[/tex]
The probability that a randomly selected car along the same portion of the highway was a speeding sports car [tex]\boxed{0.182{\text{ or 18}}{\text{.2\%}}}[/tex].
Learn more:
1. Learn more about unit conversion https://brainly.com/question/4837736
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Probability
Keywords: Traffic data, automobiles, 35 percent, travelling, same proportion, probability, sports car, normal car, speeding sports car, highway, license, plate registration, speed limit, exceeding, legal, interstate highway, percent, cameras.