Respuesta :

Let one number be x.
The other number is + 1.

The product of these 2 number is 156.
x (x + 1) = 156
x ² + x - 156 = 0
(x - 12)(x + 13) = 0
x = 12 or x = - 13 (rejected, whole number cannot be negative)

When x = 12
x + 1 = 13

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Answer: The two numbers are 12 and 13.
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rohitkumargupta
HELLO DEAR,

let the no. be x and (x+1)

=> x(x+1) = 156

=> x² + x = 156

=> x² + x - 156 = 0

=> x² - 13x + 12x - 156 = 0

=> x(x-13) + 12 (x-13) = 0

=> (x + 12)(x-13)

=> x = -12

AND,

X = 13


I HOPE ITS HELP YOU DEAR,
THANKS

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