There are 38 chocolates in a box, all identically shaped. there are 15 filled with nuts, 10 with caramel, and 13 are solid chocolate. you randomly select one piece, eat it, and then select a second piece. find the probability of selecting 2 solid chocolates in a row.

Total chocolates = 38
Total Solid chocolates = 13

P(2 solid chocolates) = 13/38 x 12/37 = 78/703

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Answer: The probability of selecting 2 solid chocolates in a row is 78/703.
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agaue agaue · Answer 2 · 2019-12-01T15:39:00+01:00

The probability of selecting 2 solid chocolates in a row is 0.11

Step-by-step explanation:

Total number of chocolates = 38

Probability of an outcome is the ratio of number of favorable outcome to total number of outcomes.

The probability of selecting 2 solid chocolates in a row = Probability of first piece to be solid chocolate x Probability of second piece to be solid chocolate.

Total number of solid chocolate = 13

[tex]\texttt{Probability of first piece to be solid chocolate = }\frac{13}{38}\\\\\texttt{Probability of second piece to be solid chocolate = }\frac{12}{37}[/tex]

[tex]\texttt{The probability of selecting 2 solid chocolates in a row = }\frac{13}{38}\times \frac{12}{37}\\\\\texttt{The probability of selecting 2 solid chocolates in a row = }0.11[/tex]

The probability of selecting 2 solid chocolates in a row = 0.11