The new volume of the balloon rises to the new location is 5.91 × 10⁴L.
Given the data in the question;
- Initial volume of helium; [tex]V_1 = 5.0*10^4L[/tex]
- Initial pressure; [tex]P_1 = 0.995atm[/tex]
- Initial temperature; [tex]T_1 = 32.0^oC = 305.15K[/tex]
- Final pressure; [tex]P_2 = 0.720atm[/tex]
- Final temperature; [tex]T_2 = -12.0^oC = 261.15K[/tex]
- Final Volume; [tex]V_2 =\ ?[/tex]
Combined gas law
Combined gas law joins together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.
It is expressed as;'
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
We substitute our given values into the expression above.
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\\P_1V_1T_2 = P_2V_2T_1\\\\V_2 = \frac{P_1V_1T_2}{P_2T_1}\\ \\V_2 = \frac{0.995atm*(5.0*10^4L)*261.15K}{0.720atn * 305.15K}\\\\V_2 = \frac{12992212.5LatmK}{219.708atmK}\\ \\V_2 = 5.91*10^4L[/tex]
Therefore, the new volume of the balloon rises to the new location is 5.91 × 10⁴L.
Learn more about the combined gas law here: brainly.com/question/25944795
