Respuesta :
-3i+3/4+2i-9/3-3i=(3/4-9/3) +(-3i+2i-3i)=(3/4-3)+(-4i)=(3/4-12/4)-4i=
=-9/4-4i
=-9/4-4i
Answer:
The complex number in standard form is given by:
[tex]-4i-\dfrac{9}{4}[/tex]
Step-by-step explanation:
The expression in terms of the complex number is given by:
[tex]-3i+(\dfrac{3}{4}+2i)-(\dfrac{9}{3}+3i)[/tex]
which is given by:
[tex]-3i+(\dfrac{3}{4}+2i)-(3+3i)[/tex]
Now on opening the parentheses term we have:
[tex]-3i+\dfrac{3}{4}+2i-3-3i[/tex]
( since, if the sign before the parentheses term is negative then the sign of each of the terms inside parentheses get's interchanged )
Now, on combining the like terms we have:
[tex]-3i+2i-3i+\dfrac{3}{4}-3\\\\=-4i-\dfrac{9}{4}[/tex]
