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The volume V of a fixed amount of a gas varies directly as the temperature T and inversely as the pressure P . Suppose that V=160cm3 when T=320 kelvin and P=12kg/cm2 . Find the pressure when T=240 kelvin and V=90cm3 .

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jamiexx
For this question, we can use the general gas law. Where (p1xV1/T1) = (p2xV2/T2)
In that equation, "1" means the initial value, and "2" is the new value given. 
p is the pressure, V is volume, and T is the temperature in Kelvin (if the temperature given is not in Kelvin, change it before you calculate!)

Now, simply substitute the numbers in, and we can calculate the final pressure, p2. 

12 x 160 / 320 = p2 x 90 / 240
6 = p2 x 90 / 240
p2 x 90 = 1440
p2 = 16

Therefore, your answer should be 16kg/cm2
Lanuel

The new pressure when Temperature = 240 kelvin and Volume = 160 [tex]cm^3[/tex] is equal to 16 [tex]kg/cm^2[/tex]

Given the following data:

  • Pressure 1 = 12 [tex]kg/cm^2[/tex]
  • Temperature 1 = 320 kelvin
  • Volume 1 = 160 [tex]cm^3[/tex]
  • Temperature 2 = 240 kelvin
  • Volume 2 = 160 [tex]cm^3[/tex]

To find the new pressure when Temperature = 240 kelvin and Volume = 160 [tex]cm^3[/tex]:

Mathematically, the relationship between the three variables is given by the expression:

[tex]V\; \alpha \;\frac{T}{P}\\\\V = \frac{kT}{P}[/tex]

Substituting the given parameters into the formula, we have;

[tex]160 = \frac{320k}{12} \\\\160\times 12 = 320k\\\\1920=320k\\\\k=\frac{1920}{320}[/tex]

k = 6

Now, we can find the new pressure:

[tex]P = \frac{kT}{V} \\\\P = \frac{6\times 240}{90} \\\\P=\frac{1440}{90}[/tex]

P = 16 [tex]kg/cm^2[/tex]

Read more: https://brainly.com/question/18676621

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