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The area of a rectangular playground enclosure at francis lewis hw is 500 square meters. the lenght of the playground is 5 meters longer than the width. find the dimension of the playground, in meters.

Respuesta :

A=L*W
L=W+5
A=(W+5)W
500=W²+5W
W²+5W-500=0

W=(-5+/-√(25+4*500))/2=(-5+/-√2025)/2=(-5+/-45)/2
we are going to take only positive value, so W=(-5+45)/2=20
L=W+5=20+5=25
W=20,
L=25

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