Respuesta :
In Ni(CO)₄ the stoichiometry of Ni to C is 1:4
for every 4 atoms of C is attached to one Ni atom.
this means that if there are 4 atoms of C - 1 atom of Ni
in 5.23 x 10²⁴ atoms of C -1/4 x 5.23 x 10²⁴ atoms of Ni
= 1.3075 x 10²⁴ atoms of Ni
the number of atoms rounded off to the second decimal place = 1.31 x 10²⁴ atoms
correct answer is E
for every 4 atoms of C is attached to one Ni atom.
this means that if there are 4 atoms of C - 1 atom of Ni
in 5.23 x 10²⁴ atoms of C -1/4 x 5.23 x 10²⁴ atoms of Ni
= 1.3075 x 10²⁴ atoms of Ni
the number of atoms rounded off to the second decimal place = 1.31 x 10²⁴ atoms
correct answer is E
Answer: The correct answer is Option E.
Explanation:
We are given a chemical compound having formula [tex]Ni(CO)_4[/tex]
In 1 mole of the compound, 1 mole of nickel atom, 4 moles of carbon atom and 4 moles of oxygen atom are present.
According to mole concept:
1 mole of a substance contains [tex]6.022\time 10^{23}[/tex] number of particles
Number of carbon atoms in compound = [tex]4\times 6.022\times 10^{23}[/tex]
Number of nickel atoms in compound = [tex]1\times 6.022\times 10^{23}[/tex]
We are given:
Number of carbon atoms = [tex]5.23\times 10^{24}[/tex]
To calculate the number of nickel atoms for given amount of carbon atom, we use unitary method:
When [tex]4\times 6.022\times 10^{23}[/tex] number of carbon atoms are present, then [tex]6.022\times 10^{23}[/tex] number of nickel atoms are also present.
So, when [tex]5.23\times 10^{24}[/tex] number of carbon atoms are present, then [tex]\frac{4\times 6.022\times 10^{23}}{6.022\times 10^{23}}\times 5.23\times 10^{24}=1.31\times 10^{24}[/tex] number of nickel atoms are also present.
Hence, the correct answer is Option E.
