Answer:
θ has a 60-degree reference angle and is located in quadrant II or IV
Explanation:
First, we will get the reference angle:
√3 / 3 is equivalent to 1/√3
This means that the reference angle for θ is 60
Second, we will locate the quadrant:
Based on the ASTC rule, the tan is positive in the first and third quadrants.
Since the given value is negative, therefore, θ is located in either the second or fourth quadrant
Hope this helps :)
