[tex]\bf \textit{area of a triangle}\\\\
A=\cfrac{1}{2}bh\quad
\begin{cases}
b=base\\
h=height\\
-----\\
A=5\frac{5}{6}\\
b=5
\end{cases}\implies 5\frac{5}{6}=\cfrac{1}{2}(5)h\implies \cfrac{5\cdot 6+5}{6}=\cfrac{5h}{2}
\\\\\\
\cfrac{35}{6}=\cfrac{5h}{2}\implies 70=30h\implies \cfrac{70}{30}=h\implies \cfrac{7}{3}=h\implies 2\frac{1}{3}=h[/tex]
