Respuesta :

5 = side a
3 = side c
angle B = 62 degrees
JK is side b
Use the Law of Cosines to find the length of side b. 
b^2 = a^2 + c^2 − 2ac cos(B) 
b^2 = (5^2 + 3^2) − ( 2 x 5 x 3) cos(62°) 
b^2 = (25 + 9) − 30 x 0.469 
b^2 = 34 - 30 x 0.469 
b^2 = 34 - 14.084 
b^2 = 19.916 
b = √19.916 
b = 4.463
Rounded to the nearest tenth is 4.5 mm.

Hope this helps!

The length of JK to the nearest tenth is; 4.5 mm

What is the Length of a side of the triangle?

From the given triangle, we see the following parameters;

JL = 3 mm

KL = 5 mm

angle JLK = 62 °

Use the Law of Cosines, we can find the length of JK as;

|JK| = √(3² + 5² − 2(3 * 5) cos62°)

|JK| = √(34 - 14.084)

|JK| = 19.916

|JK| = √19.916

|JK| = 4.463

Approximating to the nearest  tenth; JK = 4.5 mm

Read more on length of a triangle at; https://brainly.com/question/385308

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