[tex]\bf \begin{array}{llll}
\textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}
\end{array}\qquad \qquad\qquad
\begin{array}{llll}
\textit{volume of a cylinder}\\\\
V=\pi r^2 h\implies 3\left(\frac{\pi r^2 h}{3} \right)
\end{array}[/tex]
now, notice, the volume of the cylinder is really about the same as the volume of a cone, just 3 times larger, assuming "h"eight and "r"adius for both is the same amount.
now, if we know the cone with that "h" and "r" has a volume of 6π, the cylinder is.... well, you already know.
