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The data set below represents the total number of touchdowns a quarterback threw each season for 10 seasons of play.

29, 5, 26, 20, 23, 18, 17, 21, 28, 20

1. Order the values:
5, 17, 18, 20, 20, 21, 23, 26, 28, 29

2. Determine the median:
= = 20.5

Calculate the measures of variability for the data set.

The range is ___ touchdowns. The interquartile range is ____ touchdowns.

Respuesta :

Here are your measures of variability. The range is found by subtracting the highest and the lowest (29-5=24). To find the interquartile range, you will find the median of the lower half of the data and the median of the higher half of sta and subtract these 2 numbers. Here is your list. I have PUT PARENTHESES around the upper and lower quartiles: 5, 17, (18), 20, 20, 21, 23, (26), 28, 29. It is like finding the middle of the entire set of data and then finding the middle of each half. Subtract 26 and 18 to find the interquartile range of 8 touchdowns.

The range is 24 and the interquartile range is the difference between the median of the second-half to the first-half is 8.

What is a median?

The median of the data is the middle value of the data which is also known as the central tendency of the data and is known as the median.

The data set below represents the total number of touchdowns a quarterback threw each season for 10 seasons of play.

29, 5, 26, 20, 23, 18, 17, 21, 28, 20

Arrange in ascending order, we have

5, 17, 18, 20, 20, 21, 23, 26, 28, 29

The range will be given as

→ Range = 29 - 5 = 24

The interquartile range will be given as

→ Interquartile range = median of second-half - median of first-half

→ Interquartile range = 26 - 18

→ Interquartile range = 8

The range is 24 and the interquartile range is 8.

More about the median link is given below.

https://brainly.com/question/300591

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