Answer:
sin (C)
Explanation:
In a right-angled triangle, special trig functions can be applied. These functions are as follows:
sin (theta) = [tex] \frac{opposite}{hypotenuse} [/tex]
cos (theta) = [tex] \frac{adjacent}{hypotenuse} [/tex]
tan (theta) = [tex] \frac{opposite}{adjacent} [/tex]
Now, let's check the triangle we have:
We have two options:
First option:
5 is the hypotenuse of the triangle
4 is the side adjacent to angle B
Therefore, we can apply the cos function:
cos (B) = [tex] \frac{4}{5} [/tex]
Second option:
5 is the hypotenuse of the triangle
4 is the side opposite to angle C
Therefore, we can apply the sin function:
sin (C) = [tex] \frac{4}{5} [/tex]
Among the two options, the second one is the one found in the choices. Therefore, it will be the correct one.
Hope this helps :)
