The molality of a solution prepared by dissolving 175 g of KNO₃ in 750 g of water is 2.3m.
Molaity is used to define the concentration of any material present in any substance and it will be calculated as:
Molality = Moles of solute / kilograms of solvent
According to the question,
Mass of solute KNO₃ = 175g
Mass of solvent = 750g = 0.75kg
Moles of solute KNO₃ will be calculated as:
n = W/M, where
W = given mass
M = molar mass = 101.1 g/mol
n = 175 / 101.1 = 1.73 moles
On putting values, we get
m = 1.73 / 0.75 = 2.3m
Hence molality of given sample is 2.3m.
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