To solve the problem we will first name all the points given to us, and then we will find ∠O, and then we will find the value of x.
The value of x is 22°.
Given to us
Looking at the diagram below,
What is an isosceles triangle?
In ΔAOB
OA = OB = R, the radius of the circle O,
therefore, the ΔAOB is an isosceles triangle, with OA, OB as the congruent sides and AB as the base of the triangle.
Thus, ∠OAB = ∠OBA = 56°
What is the sum of all the angles of a triangle?
Sum of all the angles of a triangle = 180°
∠O + ∠AOB + ∠OBA = 180°
We know ∠AOB = ∠OBA, therefore,
∠O + 2(∠AOB) = 180°
∠O + 2(56°) = 180°
∠O = 68°,
In ΔOBC,
BC is the tangent to the circle O, therefore,
∠OBC = 90°
Sum of all the angles of a triangle = 180°
∠O + ∠OBC + ∠OCB = 180°
68° + 90° + ∠OCB = 180°
∠OCB = 180° - 68° - 90°
∠OCB = 22°
Hence, the value of x is 22°.
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