Respuesta :

mathstudent55
[tex] \tan x = \dfrac{\sin x}{\cos x} [/tex]

[tex] \tan x = \dfrac{\frac{5}{13}}{\frac{12}{13}} [/tex]

[tex] \tan x = \dfrac{5}{13} \times \dfrac{13}{12} [/tex]

[tex] \tan x = \dfrac{5}{12} [/tex]
[tex]cos x = \frac{a}{h} [/tex] , so a = 12, h = 13
[tex]sinx= \frac{o}{h} [/tex], so o = 5, h = 13
[tex]tanx = \frac{o}{a} [/tex]
[tex]tanx = \frac{5}{12} [/tex] 

Or 

[tex]tanx = \frac{sinx}{cosx} [/tex]
[tex]tanx = \frac{ \frac{5}{13}}{ \frac{12}{13} } [/tex]
[tex]tanx = \frac{5}{12} [/tex] 

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