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A pea plant that is homozygous for yellow pods with wrinkled seeds (ggrr) is cross-bred with a pea plant that is heterozygous for green pods with round seeds (ggrr). how many different genotypes will the offspring of these parents have? what percentage of offspring will have each genotype?

Respuesta :

The correct genotypes of the parents are ggrr for yellow pods with wrinkled seeds and GgRr for heterozygous for green pods with round seeds.
If the heterozygous individuals for both traits express have green pods and round seeds that tells us that these traits are dominant.
In the gross presented below, you can see that the offspring will have 4 different genotypes, all present in an equal percentage:
gGrR 25% 
gGrr  25% 
ggrR 25%
ggrr 25%

Ver imagen smilodon

Based on the genotype of the parent pea plants, 25% of offspring will have each phenotype.

What is genotype?

Genotype is the sum total of the genes inherited from both parents by offspring.

In a cross between the pea plants with the genotype below, the genotype of the offspring is given as follows:

  • ggrr × GgrRr = GgRr, ggRr, gGRr, ggrr

Therefore, 25% of offspring will have each phenotype.

Learn more about about genotype at: https://brainly.com/question/902712

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