Answer:
The product of [tex]\left(3a+2c\right)\left(9a^2-6ac+4c^2\right)=8c^3+27a^3[/tex]
Step-by-step explanation:
Given: Polynomial [tex]\left(3a+2c\right)\left(9a^2-6ac+4c^2\right)[/tex]
We have to place the indicated product in the proper location o the grid.
Consider the given product [tex]\left(3a+2c\right)\left(9a^2-6ac+4c^2\right)[/tex]
Using distributive property, Multiply each term of first bracket with each term of last bracket, we have,
[tex]=3a\cdot \:9a^2+3a\left(-6ac\right)+3a\cdot \:4c^2+2c\cdot \:9a^2+2c\left(-6ac\right)+2c\cdot \:4c^2[/tex]
Apply plus-minus rule [tex]+\left(-a\right)=-a[/tex] , we have,
[tex]=3\cdot \:9a^2a-3\cdot \:6aac+3\cdot \:4ac^2+2\cdot \:9a^2c-2\cdot \:6acc+2\cdot \:4c^2c[/tex]
Simplify, we have,
[tex]=27a^3-18a^2c+12ac^2+18a^2c-12ac^2+8c^3[/tex]
Adding similar terms, we have,
[tex]=8c^3+27a^3[/tex]
Thus, The product of [tex]\left(3a+2c\right)\left(9a^2-6ac+4c^2\right)=8c^3+27a^3[/tex]
Location on grid is as shown below
