Answer:
The length of DD' is [tex]\sqrt{29}[/tex] or 5.39 units.
Step-by-step explanation:
The distance formula is
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
From the given figure it is clear that the coordinates of D are (2,0) and coordinates of D' are (7,2).
Using distance formula we get
[tex]DD'=\sqrt{(7-2)^2+(2-0)^2}[/tex]
[tex]DD'=\sqrt{25+4}[/tex]
[tex]DD'=\sqrt{29}[/tex]
[tex]DD'\approx 5.39[/tex]
Therefore the length of DD' is [tex]\sqrt{29}[/tex] or 5.39 units.
