Respuesta :

The distance of CC' is 5.39 units.

Answer:

The length of CC' is, [tex]\sqrt{29}[/tex]units

Step-by-step explanation:

Using distance(D) formula for any two points is given by:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

As per the statement:

From the graph:

The coordinates of C and C' are:

C = (2, 2) and C' = (7, 4)

Apply the distance formula to find length CC', we have;

[tex]CC'= \sqrt{(7-2)^2+(4-2)^2}[/tex]

⇒[tex]CC'= \sqrt{(5)^2+(2)^2}[/tex]

⇒[tex]CC'= \sqrt{25+4}[/tex]

Simplify:

[tex]CC'= \sqrt{29}[/tex]

therefore, the length of CC' is, [tex]\sqrt{29}[/tex] units

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