Answer:
[tex]307.72 in^2\\[/tex]
Step-by-step explanation:
The diameter of hot water heater [tex]= 20"\\[/tex]
There is overhang of [tex]4"\\[/tex]
Thus the new extended radius of the base of hot water heater is
[tex]= \frac{20"}{2} + 4"\\= 10" + 4"\\= 14"\\[/tex]
The heater must be of circular shape, thus the area of the water heater
[tex]=\pi r^{2} \\= \pi (\frac{d}{2})^2\\= (3.14)(0.5)(14")^2\\= 307.72 in^2\\[/tex]
