Respuesta :
Let's assume
the price of each train ticket is x
we are given
total number of family members =5
so, total cost of ticket = total number of family members*the price of each ticket
so, total cost of ticket =5*x
so, total cost of ticket =5x
now, we have
each family member buys a boxed lunch for $6.50
so, total cost of lunch box = total number of family members*price of each lunch box
so, total cost of lunch box = 5*6.50
total cost of trip = total cost of ticket+total cost of lunch box
we are given
total cost of trip is $248.50
now, we can plug values
and we get
[tex] 248.50=5x+5*6.50 [/tex]
now, we can solve for x
[tex] 248.50=5x+32.5 [/tex]
[tex] 248.50-32.5=5x+32.5-32.5 [/tex]
[tex] 216=5x [/tex]
[tex] \frac{5x}{5} =\frac{216}{5} [/tex]
[tex] x=43.2 [/tex]
so,
the price of each train ticket is $43.2..........Answer
The price of each train ticket can be calculated by generating the algebraic expression as per the question.
The price of each train ticket is $43.2.
Given:
The family member is 5.
The lunch box cost is $6.50.
The total cost of the trip is $248.50.
Let price of each train ticket is [tex]x[/tex].
The total cost of ticket is multiplication of total number of family members and the price of each ticket.The mathematical expression is,
[tex]\rm{ Total\: cost \:of \:ticket} =5x\\[/tex]
Write the expression for total cost of trip.
[tex]248.50=5x+5\times 6.50\\248.50=5x+32.5\\216=5x\\x=43.2[/tex]
Thus, the price of each train ticket is $43.2.
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