Respuesta :
A=1/2BHÂ
2A=BHÂ
112 =BHÂ
We are looking for every combination of integers to multiply to 112Â
1*112
2*56
4*28
7*16
8*14
14*8
16*7
28*4
56*2
1*112
2A=BHÂ
112 =BHÂ
We are looking for every combination of integers to multiply to 112Â
1*112
2*56
4*28
7*16
8*14
14*8
16*7
28*4
56*2
1*112
A = [tex] \frac{1}{2} [/tex]b*h
b*h = 2A = 112 = 2^4*7 . . . . . . . has 10 divisors: 1, 2, 4, 7, 8, 14, 16, 28, 56, 112
So, you have
.. (b, h) = any of (1, 112), (2, 56), (4, 28), (7, 16), (8, 14), (14, 8), (16, 7), (28, 4), (56, 2), (112, 1)
b*h = 2A = 112 = 2^4*7 . . . . . . . has 10 divisors: 1, 2, 4, 7, 8, 14, 16, 28, 56, 112
So, you have
.. (b, h) = any of (1, 112), (2, 56), (4, 28), (7, 16), (8, 14), (14, 8), (16, 7), (28, 4), (56, 2), (112, 1)