Respuesta :

Solve the following system using elimination:
{2 x - 3 y = -1 | (equation 1)
{y = x - 1 | (equation 2)

Express the system in standard form:
{2 x - 3 y = -1 | (equation 1)
{-x + y = -1 | (equation 2)

Add 1/2 × (equation 1) to equation 2:
{2 x - 3 y = -1 | (equation 1)
{0 x - y/2 = (-3)/2 | (equation 2)

Multiply equation 2 by -2:
{2 x - 3 y = -1 | (equation 1)
{0 x+y = 3 | (equation 2)

Add 3 × (equation 2) to equation 1:
{2 x+0 y = 8 | (equation 1)
{0 x+y = 3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 4 | (equation 1)
{0 x+y = 3 | (equation 2)
Collect results:
Answer:  {x = 4, y = 3

The solution for the system of equations 2x - 3y = -1 and y = x - 1 is:

x = 4, y = 3

The given system of equations is:

2x - 3y = -1.........(1)

y = x - 1.........(2)

Rearrange equation (2) to be in the same form as equation (1)

-x + y = -1.........(3)

Multiply equation (3) by 2

-2x + 2y = -2......(4)

Add equations (1) and (3)

-y = -3

Multiply both sides by -1

y = 3

Substitute y = 3 into equation (2)

y = x - 1

3 = x - 1

x = 3 + 1

x = 4

Therefore the solution for the system of equations 2x - 3y = -1 and y = x - 1 is:

x = 4, y = 3

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