While holding the 80.0-N weight, the person raises his forearm until it is at an angle of 53.0 ∘ above the horizontal. If the biceps muscle continues to exert its force perpendicular to the forearm, what is this force when the forearm is in this position?

Question

05-02-2018
Physics

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While holding the 80.0-N weight, the person raises his forearm until it is at an angle of 53.0 ∘ above the horizontal. If the biceps muscle continues to exert its force perpendicular to the forearm, what is this force when the forearm is in this position?

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skyluke89 skyluke89 · Answer 1 · 2018-02-12T18:29:08+01:00

Hello

The weight of the object is W=80 N and points downwards, in the vertical direction. The force F exerted by the forearm is perpendicular to the forearm itself, which is at an angle of [tex]\theta=53^{\circ}[/tex] above the horizontal; therefore, the angle between the direction of the force F and the direction of the weight P is also [tex]\theta=53^{\circ}[/tex] (but upwards). The component of the force F in the vertical direction is
[tex]F_y=F cos \theta[/tex]
and [tex]F_y[/tex] must be equal to the weight of the object to compensate it. Therefore we can write
[tex]F_y= F cos\theta = P[/tex]
and from this we can find the intensity of the force F:
[tex]F= \frac{P}{cos \theta}= \frac{80~N}{cos 53^{\circ}}=132.9~N [/tex]

tifanihayyu tifanihayyu · Answer 2 · 2019-08-28T22:59:14+02:00

The force when the forearm is in this position is 453.74 N

Further explanation

Free body diagram (FBD) is a graphical illustration to visualize the applied forces, movements, and resulting reactions on a body in a given condition. Free body diagram of the forearm and hand (Static equilibrium) is shown in the figure below. The drawing of a free-body diagram is an important step in the solving of mechanics problems

While holding the 80.0-N weight, the person raises his forearm (the part of the arm between the wrist and the elbow) until it is at an angle of 53.0 ∘ above the horizontal. If the biceps muscle (a large muscle lies on the front of the upper arm between the shoulder and the elbow) continues to exert its force perpendicular to the forearm, what is this force when the forearm is in this position?

[tex]d = a cos \theta[/tex]

[tex]\Sigma \tau_O = 0[/tex] => [tex]aF_B - (bcos\theta)W - c(cos\theta)(80) = 0[/tex]

[tex]F_B = \frac{|bW+c*(80.0)|}{a} cos\theta[/tex] (Equation 1)

[tex]F_B = \frac{|0.150*15+0.33*(80.0)|}{0.038} cos\theta[/tex]

The green expression is equivalent to [tex]F_B[/tex]

[tex]F_B = (753.95) cos 53 = 453.74 N[/tex]

Learn more

Learn more about the biceps muscle https://brainly.com/question/3140761
Learn more about the forearm https://brainly.com/question/9081105
Learn more about force https://brainly.com/question/11869811

Answer details

Grade: 9

Subject: physics

Chapter: force

Keywords: the biceps muscle, the forearm, force, physics, perpendicular