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To model this situation, we are going to use the exponential function: [tex]f(t)=P(1+ \frac{r}{n} )^{nt}[/tex]
where
[tex]P[/tex] is the initial number of cars
[tex]r[/tex] is the growing rate in decimal form 
[tex]n[/tex] is number of tames the growing rate is increasing per year
[tex]t[/tex] is the time in years

To convert the growing rate to decimal form, we are going to divide the rate by 100%
[tex]r= \frac{12}{100} [/tex]
[tex]r=0.12[/tex]
Since the growing rate is increasing quarterly, [tex]n=4[/tex]. We also know that the initial number of cars is 920, so [tex]P=920[/tex]. Lets replace all those values in our function:
[tex]f(t)=920(1+ \frac{0.12}{4} )^{4t}[/tex]
[tex]f(t)=920(1+0.03)^{4t}[/tex]
[tex]f(t)=900(1.03)^{4t}[/tex]

We can conclude that:
Rate ---------> The quarterly rate of growth is 0.03 or 3%
Exponent --------> The compound periods multiplied by the number of years                                 is 4t
Coefficient--------> The initial number of cars serviced is 920
Base------> The growth factor is represented by 1.03

Answer:

see below

Step-by-step explanation:

Rate: tile saying the quarterly rate of growth is 0.03 or 3%

Exponent: tile saying the growth factor is represented by 1.03

Coefficient: tile saying the compound periods multiplied by number of years is 4t

Base: tile saying the initial number of cars serviced is 920

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