Respuesta :

10x-4x^2-7x-a=3x-6x^2
3x-4x^2-a=3x-6x^2
a=6x^2-4x^2
a=2x^2

Answer:

Let the missing number be a.

Given that:

[tex](10x-4x^2)-(7x+a) = 3x-6x^2[/tex]

Remove the parenthesis we have;

[tex]10x-4x^2-7x-a= 3x-6x^2[/tex]

Combine like terms we have;

[tex]3x-4x^2-a= 3x-6x^2[/tex]

Subtract 3x from both sides we have;

[tex]-4x^2-a=-6x^2[/tex]

Add [tex]4x^2[/tex] to both sides we have;

[tex]-a=-6x^2+4x^2[/tex]

Simplify:

[tex]-a=-2x^2[/tex]

Divide both sides by -1 we have;

[tex]a=2x^2[/tex]

Therefore, the missing term is, [tex]2x^2[/tex]

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