A charge of 9.0 × 10–5 C is placed in an electric field with a strength of 4.0 × 104 . What is the electrical force acting on the charge?

Respuesta :

The answer is 3.6 newtons.

Answer:

3.6 N

Explanation:

The electrical force acting on the charge is given by:

[tex]F=qE[/tex]

where

q is the charge

E is the strength of the electric field

In this problem, we have

[tex]q=9.0\cdot 10^{-5} C[/tex]

[tex]E=4.0\cdot 10^4 N/C[/tex]

Substituting into the formula, we find the electrical force:

[tex]F=(9.0\cdot 10^{-5} C)(4.0\cdot 10^4 N/C)=3.6 N[/tex]

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