What is the graph of the system y = −2x + 3 and 2x + 4y = 8?
A. line through point (0, 3) and (1, 1). Line through (0, negative 2) and (negative 4, 0)
B. line through point (0, 3) and (1, 1). Line through (0, 2) and (negative 4, 0)
C. line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0)
D. line through point (0, 3) and (1, 1). Line through (0, negative 2) and (4, 0)

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skykiyo123ouae6s skykiyo123ouae6s · Answer 1 · 2018-02-05T17:33:50+01:00

You answer is:
Line through point (0,3) and (-1,1). Line through (0,2) and (4,0)
The one that resembles this the most is letter C

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lublana lublana · Answer 2 · 2019-07-25T11:19:26+02:00

Answer:

The line passing through points (0,3) and (1.5,0) . Line through (0,2) and (4,0).

Step-by-step explanation:

We are given that two equations

[tex] y=-2x+3[/tex]...(I equation )

[tex] 2x+4y=8[/tex]....(II equation)

We have to find the the graph of the given system

We solve first I equation

Substitute x=0 in equation I then we get

[tex]y=3 [/tex]

Now, we substituting y= 0 then we get

[tex]0=-2x+3[/tex]

[tex]2x=3[/tex]

[tex]x=\frac{3}{2}=1.5[/tex]

[tex]x=1.5[/tex]

Hence, the line[tex] y=-2x+3[/tex] passing through the points (0,3) and (1.5,0).

We are solving equation II

Substitute x= 0 in II equation

Then we get [tex] 4y=8[/tex]

[tex] y=\frac{8}{4}=2[/tex]

[tex]y=2[/tex]

Now, we substituting y=0 then we get

[tex]2x=8[/tex]

[tex] x=\frac{8}{2}[/tex]

[tex]x=4[/tex]

Therefore, the equation [tex]2x+4y=8[/tex] is passing through the points (0,2) and (4,0).

But any option does not match.