Answer: The perimeter of the garden is: " 102 ft. " .
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Note:
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→ P = 2L + 2w ;
in which: "P = perimeter (for which we wish to solve)" ;
"L = length = 10 yds. (given) " ;
"w = width = 7 yds. (given)" .
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Plug in the given values; and solve for the perimeter, "P" :
→ P = 2L + 2w ;
= 2(10) + 2(7) ;
= 20 + 14 ;
= 34 yds.
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The perimeter is: 34 yds.
Now, we are asked to convert this into: "feet (ft.)." .
Note the "exact conversion" : "3 ft. = 1 yd." ;
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→ 34 yds. * [tex] \frac{3 ft}{1 yd} [/tex] = (34 * 3) ft. = 102 ft.
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Answer: The perimeter of the garden is: " 102 ft. " .
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