Here the figure is sum of a square and a right angled triangle.
We know that square has equal four sides. Here the length of the side of square = 10 inch.
We know that formula to find area of a square is [tex] a^2 [/tex], where a is the side of the square.
By substituting the value of a in the formula we will get,
The area of the square = [tex] (10)^2 [/tex] = 100 square inches.
Now we have the right angled triangle.
To find the base of the triangle we will subtract 6 from the side length of the square.
So base of the triangle = [tex] (10-6) [/tex] = 4 inches.
To get height of the triangle we will subtract the side length of the square from 16. We will get,
[tex] (16-10) [/tex] = 6 inches.
Now we know that the formula to find the area of the triangle = [tex] \frac{1}{2} bh [/tex], where b is the base and h is the height.
Here we have b = 4 inches and h = 6 inches.
The area of the triangle
= [tex] \frac{1}{2}(4)(6) [/tex]
= [tex] \frac{1}{2}(24) [/tex]
= [tex] 12 [/tex]
So area of the triangle = 12 square inches.
Now total area of the figure is sum of area of the square and area of the triangle.
Total area = [tex] (100+12) [/tex] square inches = 112 square inches.
We have got the required answer.
The total area of the figure = 112 square inches.
