What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divided into six equilateral triangles.)
The area of a regular polygon given the radius is: [tex]area= \frac{r^2*n*sin(\frac{360}{n})}{2}[/tex] given: r=1 n=6 Then the area will be: [tex]area= \frac{1^2*6*sin(\frac{360}{6})}{2}[/tex] area=[tex] \frac{3 \sqrt3}{2}[/tex] cm²
