Respuesta :

[x-(-1+i)][x-(-1-i)]
[(x+1)-i][(x+1)+i]
(x+1)²-i²
(x²+2x+1)+1
x²+2x+2
so the answer is 2x

Answer:

The Roots of the equation which is in Quadratic form  are:

    [tex]x= -1 \pm i\\\\ x +1=\pm i\\\\ \text{Squaring both sides}}\\\\ (x+1)^2=(\pm i)^2\\\\ x^2 +2 x +1= -1\\\\x^2+2 x +2=0[/tex]

The Equation is

 x²+2 x +2=0

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