Respuesta :

1.75+0.43301270i
hope this helped and let me know if i was right plz

Answer:

[tex]\frac{7}{4} +\frac{3}{4} i[/tex]

Step-by-step explanation:

[tex](1+2\sqrt{-3} )/(1+\sqrt{-3})[/tex]

To remove the negative sign from square root use 'i'

square root (-1) is 'i'

[tex]\frac{1+2\sqrt{3}i}{1+\sqrt{3}i}[/tex]

Multiply top and bottom by conjugate of [tex](1+\sqrt{3}i)[/tex]

Conjugate of [tex](1+\sqrt{3}i)[/tex] is [tex](1-\sqrt{3}i)[/tex]

Multiply it at the top and bottom

[tex]\frac{1+2\sqrt{3}i}{1+\sqrt{3}i} \cdot \frac{1-\sqrt{3}i}{1-\sqrt{3}i}[/tex]

Multiply numerator and denominator using FOIL method

[tex]\frac{1-\sqrt{3}i+2\sqrt{3}i-3i^2}{1+3}[/tex]

the value of i^2 is -1

[tex]\frac{1+\sqrt{3}i-6(-1)}{4}[/tex]

[tex]\frac{1+\sqrt{3}i+6}{4}[/tex]

[tex]\frac{7+\sqrt{3}i}{4}[/tex]

[tex]\frac{7}{4} +\frac{3}{4} i[/tex]

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